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La función $f(x) = \left\{\begin{array}{cc} \frac{x^2-1}{x-1} & \text{si } x > 1 \\ 5x + a & \text{si } x \leq 1 \end{array}\right.$ es continua en $x_0 = 1$ si
$\circ a=-5$
$\circ a=-3$
$\circ a=2$
$\circ a=5$